Ning Zhu edited Figures.tex  over 8 years ago

Commit id: 557b8603810e870df5257396275d4d439d5b3e91

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As shown in Figure 2:  $$V=0.000443B+0.127$$  Therefore:  $$\frac{\Delta V}{\Delta B}=0.000443\frac{V}{mT}=0.443\frac{V}{T} B}=0.000443\frac{V}{mT}=0.443\frac{V}{T}$$  As shown in Figure 1:   $$V=\frac{0.021\times (1+cos(\frac{2\pi\times(\theta-162)}{180}))}{2}$$