Nathanael A. Fortune edited subsubsection_Johnson_noise_in_1K__.tex  over 8 years ago

Commit id: deadce64dc4c43fe75dcd278aea3a88b91cc6464

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\subsubsection{Johnson noise in $1K$ Ohm Resistor}  Our settings for the Noise Fundamentals devices were as follows: $1K$ ohm resistor, we used a Gain 1 (G1) of $600$ for all values that comes directly from the Noise Fundamental device, a Gain 2 (G2) of $1000$ for all values, we used a room temperature of $296.15$ degrees Kelvin, and we varied the high and low pass filters' frequency for each data set in order to vary the bandwidth. In Table 1, you can see how we varied the low pass filter (f2) and the high pass filter (f1) in order to change the bandwidth. The values are taken from the multi-meter after going through the filters, gain, and multiplier. multiplier\textbf{ (are these the values after being multiplied, or after passing through the $A \times A$ multiplier and then being divided by 10 Volts?)}  All of the values are in mV; we took $36$ sets of data points. You can see all these values in Table 2. \textbf{This is better than the explanation for the 0 \textrm{ k}\Omega$ data, but it still isn't as clear as it could be. It would really help to have an equation here. For example, I'm not sure if you are saying the values in the table are $V_{\textrm{meter}} = (^2 + ^2) G_1 G_2 / (10 \textrm{Volts}) \textrm{ [mV]}$, and, as a result, the values in the table are voltages, or that they are $(^2 + ^2) G_1 G_2$ and are in units of voltage squared? If so, why not make it clear by saying that?}