deletions | additions       diff --git a/textbf_EDITOR_S_NOTE_the__1.tex b/textbf_EDITOR_S_NOTE_the__1.tex  index c968137..ec2b94a 100644  --- a/textbf_EDITOR_S_NOTE_the__1.tex  +++ b/textbf_EDITOR_S_NOTE_the__1.tex 
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\item $^2$ + $^2$ isn't a voltage, it is a voltage squared, so it can't be the voltage the multimeter measures.   \item the averages $$ and $$ would be zero, as they are ac voltages that are just as likely to be negative as positive. That's why we square them BEFORE averaging them!   \item $\sqrt{<(V_{signal})^2>} = \sqrt{<(V_J)^2> + <(V_{amplifiers})^2>}$ is the average RMS ac voltage from the resistor $R_in$ and measurement circuit (before correcting for noise from the circuit)  \end{enumerate} Finally, and equally importantly, the equation you have given can't be what was used to calculate the values in Table 1 if the values in Table 1 are in Volts squared!   MIGHT THE VALUES IN TABLES 1 and 2 REALLY BE $<(V_J)^2> + <(V_{amplifiers})^2> G_1 G_2$ ?