this is for holding javascript data
Nathanael A. Fortune added textbf_EDITOR_S_NOTE_the__1.tex
over 8 years ago
Commit id: 596bec9b842ba7eea9f8fb4558d78fa9ee32133c
deletions | additions
diff --git a/textbf_EDITOR_S_NOTE_the__1.tex b/textbf_EDITOR_S_NOTE_the__1.tex
new file mode 100644
index 0000000..c968137
--- /dev/null
+++ b/textbf_EDITOR_S_NOTE_the__1.tex
...
\textbf{EDITOR'S NOTE}
the factor of 10 does NOT come from the G1 and G2 amplifiers. It comes from a x$\frac{1}{10}$ multiplier (or, if you wish, a x$10 V$ divider) that divides the output of the multiplier (in Volts squared) by 10 Volts before sending the signal on to the BNC connector for the multimeter.
$^2 + ^2$ isn't the measured voltage from the multimeter.
\begin{enumerate}
\item the noise voltages aren't \textit{from} the multimeter, they're \textit{from} the resistor $R_in$ that is the source of the Johnson noise and the amplifier circuit that is the source of the instrumentation noise .
\item $^2$ + $^2$ isn't a voltage, it is a voltage squared, so it can't be the voltage the multimeter measures.
\item the averages $$ and $$ would be zero, as they are ac voltages that are just as likely to be negative as positive. That's why we square them BEFORE averaging them!
\item $\sqrt{<(V_{signal})^2>} = \sqrt{<(V_J)^2> + <(V_{amplifiers})^2>}$ is the average RMS ac voltage from the resistor $R_in$ and measurement circuit (before correcting for noise from the circuit)
\end{enumerate}
