this is for holding javascript data
Nathanael A. Fortune edited EDITOR_S_NOTE_The_above__.tex
over 8 years ago
Commit id: 2ea3f506864e6c1d6743804870e52a349eda4afd
deletions | additions
diff --git a/EDITOR_S_NOTE_The_above__.tex b/EDITOR_S_NOTE_The_above__.tex
index dd17c6f..3672855 100644
--- a/EDITOR_S_NOTE_The_above__.tex
+++ b/EDITOR_S_NOTE_The_above__.tex
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\begin{enumerate}
\item a voltage cannot equal a voltage squared, so $V \neq <(V)^2>$ and $V_{mult} \neq (V_J + V_{\textrm{other noise}})^2>$
\item YOu should write $<(V_J)^2> +
<(V_{other})^2$, <(V_{other})^2$>, not
$(V_J $<(V_J + V_{\textrm{other
noise}})^2$. noise}})^2>$. There are two independent (random) noise sources --- the resistor being measured (Johns) and the amplifier circuits (instrumentation) ---so you don't add their voltages $V_{Johnson}$ and $V_{instrumentation}$, you need to add $<(V_{\textrm{Johnson Noise}})^2>$ and $<(V_{\textrm{instrument noise}})^2>$. See textbook and manual.
\item if $V_{Mult}$ means the \textit{multiplication} of two voltage signals $V_s \times V_s$ , it should be written $V^2_{mult}$
\item if $V_{Mult}$ means the voltage signal measured by a \textit{multimeter}, then it should read $V^2_{multimeter}$ = $(V_s \times V_s) / (10 \ V)$ since the output of the multiplier is divided by a 10 V reference signal before being sent to the multimeter
\end{enumerate}