deletions | additions       diff --git a/subsubsection_Charge_Density_Since_we__.tex b/subsubsection_Charge_Density_Since_we__.tex  index ddf5f2a..b5db6d1 100644  --- a/subsubsection_Charge_Density_Since_we__.tex  +++ b/subsubsection_Charge_Density_Since_we__.tex 
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\subsubsection{Charge Density}  Since we know that both have positive and negative muons contribute to the mean muon lifetime, it is also important to have some sort of quantitative understanding of the ratio, $\rho$ of muons to antimuons is. We can calculate $\rho$ via Equation 5.\cite{MuonPhysics}  \begin{equation}  \rho=-\frac{\tau^{+}}{\tau^{-}}(\frac{\tau^{-}-\tau_{obs}}{\tau^{+}-\tau_{obs}})=\frac{N^{+}}{N^{-}}  \end{equation}  Where $\tau^{+}$ is the known value of the mean lifetime for an antimuon,$2.19 \mu\textrm{seconds}$, $\tau^{-}$ is the known value of the mean lifetime for a muon, $2.03 \mu\textrm{seconds}$, and $\tau_{obs}$ is the value $2.04\pm0.04 \mu\textrm{seconds}$, taken from the best fit of our data.   Thus the calculated ratio is approximately $0.072\pm.001$. This value is quite small, which confirms our previous hypothesis that the number of muon decays detected was significantly greater than the number of antimuon decays detected.  \subsubsection{Fermi Coupling Constant}  The Fermi Coupling Constant is the strength of the weak force, and can be calculated from the observed muon lifetime, $\tau_{obs}$. The relationship between the muon lifetime and the Fermi Coupling Constant is shown below,\cite{MuonPhysics}  \begin{equation}  \tau=\frac{192\pi^{3}\hslash^{7}}{G_{f}^{2}m^{5}c^{4}}  \end{equation}  
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\begin{equation}  G_{f}=\sqrt[]{\frac{192\pi^{3}\hslash^{7}}{\tau m^{5}c^{4}}}  \end{equation}  From