Madeline Horn edited After_removing_the_background_maxima__.tex  over 8 years ago

Commit id: f93fa44a8af4cb32717cd76d41a4f594cf92962e

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Once these values were found, the measured spacings, ($\Delta E_{n}$), between the maxima and minima of the Franck-Hertz curve were plotted against the minimum order (n) of the peaks and dips and analyzed using a linear fit (Figure 6). The lowest excitation energy of Mercury was determined from the graph by finding the intercept of the linear fit at $n=0.5$.   \begin{equation}  \begin{split}  E_n E_a  [eV] (Peaks) & = (0.1040\pm0.04)n + (4.573\pm0.19)\\ E_a [eV] (Peaks) &=(0.1040\pm0.04)(0.5) + (4.573\pm0.19)\\  E_a [eV] (Peaks) &=4.63\pm.23  \end{split} 

\begin{equation}  \begin{split}  E_n E_a  [eV] (Dips) &= (0.0660\pm0.05)n + (4.686\pm0.20)\\ E_a [eV] (Dips) &= (0.0660\pm0.05)(0.5) + (4.686\pm0.20)\\  E_a [eV] (Dips) &= 4.72\pm.25\\  \end{split}