deletions | additions       diff --git a/section_Theory_cite_Melissinos_as__.tex b/section_Theory_cite_Melissinos_as__.tex  index 759a367..518b630 100644  --- a/section_Theory_cite_Melissinos_as__.tex  +++ b/section_Theory_cite_Melissinos_as__.tex 
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\Delta E__{\textrm{atom, n}} = E_n - E_{n-1} = [1+ \frac{\lambda}{L} {(2n-1)}] E_a \textrm{ [eV]}  \end{equation}  where $E_n = e V_{\textrm{acceleration}} $ is the energy of the electron at the \textit{nth} dip in electron beam current (indicating transfer of energy from electron to atom), and the mean free path $\lambda$ depends on the gas density, pressure, and temperature. \par  When $\lambda$ is very small (as is the case for a high density) gas, the second term ($\frac{\lambda}{L} {(2n-1)}E_a$) will cancel, and the expression for the long mean free path will be equivalent to the expression for the short mean free path. Since the three gases used were low-density gases, the second term is significant, and the expression for the long mean free path must be used.