William edited The_equation_found_for_Single__.tex  over 8 years ago

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E_n [eV] (fit) = (0.136\pm0.03)n + (4.35\pm0.16)  \end{equation}  Using the above equation, the intercept was found to be a value of $E_a = 4.418 \textrm{eV}$ at $n=0.5$. This value has been compared to the accepted value of $4.6674ev$ and $4.8865ev$ (cite), and the value extracted from the fit has a percent uncertainty of $5.34 \%$ and $9.59 \%$. The method used (Figure 6) proved to () values much closes to the accepted values. Thus it was concluded, concluded  that although the value of $n=2$ is not on the line of best fit, using separate linear fits to approximate $\Delta E$ versus $n$ is a better method.