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William edited From_equation_7_the_intercept__.tex
over 8 years ago
Commit id: bcbeda362e603795b5d4ff4e7b1a47ee8618bec8
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From equation 7 the intercept at $n=0.5$ is found to be $19.4
eV$. eV\pm4.2$. The value found
for $E_{a}$ using
both the short mean free limit
and ($19.54\pm1.48$) does not match the expected value of $E_{a}$ ($16.6eV$) for Neon I within uncertainty. However, the value found for $E_{a}$ using the long mean free limit
are not consistent with the known values given ($19.4\pm4.2$) does match the
estimated error. Furthermore the percent error on the values expected value of $E_{a}$
is $14.19 \%$, which is relatively high. This for Neon I within uncertainty. Thus we may
be because conclude that although the
data ionized before a sufficient amount values of
dips have been recorded. Had more dips been observed before ionization, $\Delta E$ look equivalent in Figure 4, the
intercept at $n=0.5$ might have been closer to mean free path may still be significant, since the
expected value. long mean free limit better approximates the values of $E_{a}$.