William edited Eqn_2_is_used_to__.tex  over 8 years ago

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\begin{equation}  E_a = (0.5)\Delta E  \end{equation}  Thus the lowest excitation energy of Neon was determined from the Figure 4 5  by finding the intercept of the linear fit at $n=0.5$. The value of the excitation energy found from the linear fit was then compared to the known value of the lowest excitation energy for Neon I, $16.6eV$ (cite). \begin{equation}  \begin{split}