William edited section_Theory_cite_Melissinos_as__.tex  over 8 years ago

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\end{equation}  Assuming that the experiment took place at typical tube pressures $\lambda$ should be much smaller than the distance between $G_{1}$ and $G_{2}$. Thus $\delta_{n}\ll E_{a}$ and:   \begin{equation}\label{eq:EnergyGained}   \  \delta_{n} = n\frac{\lambda}{L}E_{a} \end{equation}  Combining Equations 2 and 3, an expression for the long mean free path limit can be written:   \begin{equation}\label{eq:LongMeanFreePath}