deletions | additions       diff --git a/section_Theory_cite_Melissinos_as__.tex b/section_Theory_cite_Melissinos_as__.tex  index a55e02c..40b134f 100644  --- a/section_Theory_cite_Melissinos_as__.tex  +++ b/section_Theory_cite_Melissinos_as__.tex 
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\ E_{n} = n(E_a+\delta_n)  \end{equation}  Assuming that the experiment took place at typical tube pressures $\lambda$ should be much smaller than the distance between $G_{1}$ and $G_{2}$. Thus $\delta_{n}\ll E_{a}$ and:   \begin{equation}\label{eq:EnergyGained}   \ delta_{n} \begin{equation}\label{eq:deltan}   \delta_{n}  = n\frac{\lambda}{L}E_{a} \end{equation}  Combining Equations 2 and 3, an expression for the long mean free path limit can be written:   \begin{equation}\label{eq:LongMeanFreePath}