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Contrast two predictions:  \begin{enumerate}  \item in the short mean free path$\lambda$  limit, $\Delta E_{\textrm{atom}} = \Delta E_{\textrm{electron}} \textrm{ eV}$ \item in long mean free path$\lambda$  limit, $ \Delta E__{\textrm{atom, n}} = E_n - E_{n-1} = [1+ \frac{\lambda}{L} {(2n-1)}] E_a \textrm{ eV}$ \end{enumerate}  where $E_n$ is the \textit{nth} dip in electron beam current (indicating transfer of energy from electron to atom) and the mean free path $\lambda$  depends on the gas density, pressure, and temperature.