this is for holding javascript data
Madeline Horn edited The_equation_found_for_Single__.tex
over 8 years ago
Commit id: 2cc64f397b60ca4e939af44f07c5584bccd3d7e0
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E_n [eV] (fit) = (0.136\pm0.03)n + (4.35\pm0.16)
\end{equation}
Using the above equation, I found the intercept at $n=0.5$ to be a value of $E_a = 4.418 \textrm{eV}$. I compared this value to the accepted value of $4.6674ev$ and $4.8865ev$ (from the NIST AID data), and the value from the fit using both peaks and dips is $5.34 \%$ and $9.59 \%$ different from the accepted value. Our previous
values values, when we did not combine all of the data points onto one
fit, fit and seen in Figure: Mercury Differences in Peaks and Dips, are much closer to the accepted value. I believe this means that, although the value for $n=2$ of the dips is very off of the fit, it is a much better way to analyze the data and that the $n=2$ value does not contribute significantly to the error.