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Eqn 2 is used to estimate the lowest excitation energy of Neon. Since, $\Delta E_{atom}=\Delta E_{electron}$, and all the values of $\Delta E$ should be equivalent. Thus to find the lowest excitation energy, a mean value was found between the three data points. Thus using the short mean free limit the lowest excitation energy is found to be approximately $19.54\pm3.2$.   This value is not exceedingly better than the value found using the long mean path limit. To estimate the lowest excitation energy of Neon using the  The lowest excitation energy of Neon was determined from the Figure 4 by finding the intercept of the linear fit at $n=0.5$. The value of the excitation energy found from the linear fit was then compared to the known value of the lowest excitation energy for Neon I, $16.6eV$ (cite). \begin{equation}  E_n [eV] (Dips) = (-0.170\pm1.0)n + (19.45\pm3.2)