deletions | additions       diff --git a/Eqn_2_is_used_to__.tex b/Eqn_2_is_used_to__.tex  index 880fe32..19ac886 100644  --- a/Eqn_2_is_used_to__.tex  +++ b/Eqn_2_is_used_to__.tex 
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Eqn 2 is used to estimate the lowest excitation energy of Neon. Since, $\Delta E_{atom}=\Delta E_{electron}$, and all the values of $\Delta E$ should be equivalent. Thus to find the lowest excitation energy, a mean value was found between the three data points. Thus using the short mean free limit the lowest excitation energy is found to be approximately $19.54\pm3.2$.   This value is not exceedingly better than the value found using the long mean path limit. To estimate $E_{a}$ when the mean free path, $\lambda$, is significant, an equation for  the lowest excitation energy of Neon using can be derived from equation 5.   \begin{equation}  E_a = (0.5)\Delta E  \end{equation}  Thus  theThe  lowest excitation energy of Neon was determined from the Figure 4 by finding the intercept of the linear fit at $n=0.5$. The value of the excitation energy found from the linear fit was then compared to the known value of the lowest excitation energy for Neon I, $16.6eV$ (cite). \begin{equation}  E_n [eV] (Dips) = (-0.170\pm1.0)n + (19.45\pm3.2)