deletions | additions       diff --git a/The_equation_found_for_Single__.tex b/The_equation_found_for_Single__.tex  index af6e2b2..c7006d8 100644  --- a/The_equation_found_for_Single__.tex  +++ b/The_equation_found_for_Single__.tex 
...
\begin{equation}  \begin{split}  E_n [eV] (fit) & = &=  (0.136\pm0.03)n + (4.35\pm0.16)\\ E_a [eV] (Peaks) (fit)  &=(0.136\pm0.04)(0.03) + (4.35\pm0.16)\\ E_a [eV] (Peaks) (fit)  &=4.418\pm0.20 \end{split}  \end{equation}  \end{equation}  Using the above equation, the intercept was found to be a value of $E_a = 4.418 \textrm{eV}$ at $n=0.5$. This value has been compared to the accepted value of $4.6674ev$ and $4.8865ev$ (cite), and the value extracted from the fit has a percent uncertainty of $5.34 \%$ and $9.59 \%$. The method used (Figure 6) proved to () values much closes to the accepted values. Thus it was concluded that although the value of $n=2$ is not on the line of best fit, using separate linear fits to approximate $\Delta E$ versus $n$ is a better method.