S More edited untitled.tex  over 8 years ago

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\end{equation}  Substituting $f' = f-\mu$, $df' = df$,  \begin{equation}  I(\mu, \sigma) = \int_{-\mu}^{\infty} df' f' (f'+\mu)  \frac{1}{\sqrt{2\pi}\sigma}\exp\left(-\frac{f'^2}{2\sigma^2} \right) \end{equation}  which can be split into  \begin{equation}  I(\mu, \sigma) = \int_{-\mu}^{0} df' f' (f'+\mu)  \frac{1}{\sqrt{2\pi}\sigma}\exp\left(-\frac{f'^2}{2\sigma^2} \right) + \int_{0}^{\infty} df' f' (f'+\mu)  \frac{1}{\sqrt{2\pi}\sigma}\exp\left(-\frac{f'^2}{2\sigma^2} \right) \end{equation}  \begin{equation}