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\end{problem}  \begin{solution}  If $x$=$0$ (mod $3$),then for $x$ to be prime $x$ must be $3$. If $x$=$1$(mon$3$), then $x$ has to be $4$.  The this shows that the next $x$ will be prime relative to $3$.   We can then assume $x$=$2$$m$+$1$, and $y$=$2n$+$1$, since odd numbers can be represented as $2$$m$+$1$ and  $2n$+$1$ where $m$ and $n$ are integers.  %%%%%%%%%%%%%%%%%%%%%%%%%%%%  \begin{problem}