deletions | additions       diff --git a/paragraph_Question_2_a_Show__.tex b/paragraph_Question_2_a_Show__.tex  index 795e6e4..155ea4b 100644  --- a/paragraph_Question_2_a_Show__.tex  +++ b/paragraph_Question_2_a_Show__.tex 
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x(n) is monotone decreasing if $x(n+1)\leq x(n)$ for all $n\geq 1$.    \[ x(n+1) = \frac{1}{n+1}+\frac{1}{n+2}+\ldots +\frac{1}{2n+1} \]  Since \[ \frac{1}{n} > \frac{1}{n+1 \] for $n \geq 1$