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\\ The sequence $x(n)$ is bounded above if there is a real number U such that $x(n)\leq U$ for all $n\geq 1$.  \\Lets say $U=2$ then $x(n) \leq 2$ for all $n\geq 1$.  \\Since $\frac{1}{n^2}$ is a fraction that is  decreasing as n $\rightarrow \infty$ and x(1) = 1 we have a convergence and x(n) is bounded above by 2.