Dayo Ogundipe edited begin_itemize_item_textbf_Show__.tex  over 8 years ago

Commit id: ce53ee5d41bf04309564ded9ed8c2fe6fc1c5dd3

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$\therefore log_2(3)$ is not a rational number. Proof by contradiction.    \item Show that $\log_{\sqrt{2}}(3)$ is not a rational number  Assume that $\log_\sqrt{2} (3) = \frac{p}{q}$ where p, q are integers.    \[\sqrt{2}^{\log_{2} (3)} = 3 \]  \[ \sqrt{2}^\frac{p}{q} = 3 \]  \end{itemize}