deletions | additions       diff --git a/begin_itemize_item_textbf_sqrt__.tex b/begin_itemize_item_textbf_sqrt__.tex  index 810845c..36c1f46 100644  --- a/begin_itemize_item_textbf_sqrt__.tex  +++ b/begin_itemize_item_textbf_sqrt__.tex 
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\\ The product of two integers will always be an integer. The product of a integer and an irrational is not an integer. Since n is an integer and $\sqrt{2}$ is irrational, $n\sqrt{2}$ is not an integer.   \\ Both statements are false.  \item \textbf{Obtain a contradiction by taking n to be the smallest positive integer for which (2) is true, and so conclude that $\sqrt{2}$ is not a rational number.}  Smallest positive integer is when n = 1. Then $1\sqrt{2}$ = $\sqrt{2}$   \item \textbf{Convert the above into a structured proof that $\sqrt{2}$ is not a rational number.}  \item \textbf{Show that $\log _2(3)$ is not a rational number.}  \\