deletions | additions       diff --git a/begin_itemize_item_textbf_sqrt__.tex b/begin_itemize_item_textbf_sqrt__.tex  index 7a1fc56..969bab4 100644  --- a/begin_itemize_item_textbf_sqrt__.tex  +++ b/begin_itemize_item_textbf_sqrt__.tex 
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\\ $\therefore n^*\sqrt{2}$ is an integer.    \textbf{$n^*  \[n^*=n(\sqrt{2}-1) \]  \[\frac{n^*}{\sqrt{2}-1} = n \]  $\sqrt{2}-1$ is a number greater than zero.  \\ $\therefore n^*  \item \textbf{Obtain a contradiction by taking n to be the smallest positive integer for which (2) is true, and so conclude that $\sqrt{2}$ is not a rational number.}  \\Smallest positive integer $n> 0$ is when n = 1. Then $1\sqrt{2}$ = $\sqrt{2}$