Dayo Ogundipe edited begin_itemize_item_textbf_Show__.tex  over 8 years ago

Commit id: 977075604f64c6bfe430ca98988b0f077d24ee4a

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\\     Assume that $\log_2 (3) = \frac{p}{q}$ where p, q are integers.  Proof by contradiction.  \[2^{\log_2 (3) = 3} \]  \[ 2^\frac{p}{q} = 3 \]  \[$2^{p} - 2^{q} = 3\]  

\[ 2^p = 3^q \]  $2^p$ will always be even and $3^q$ will always be odd.    $\therefore log_2(3) $ log_2(3)$ is not a rational number. Proof by contradiction.    \item Another entry in the list  \end{itemize}