deletions | additions       diff --git a/begin_itemize_item_textbf_Show__.tex b/begin_itemize_item_textbf_Show__.tex  index 2bdb049..772b203 100644  --- a/begin_itemize_item_textbf_Show__.tex  +++ b/begin_itemize_item_textbf_Show__.tex 
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\item \textbf{Show that $\log_{10}(2)$ is not a rational number.}  \[ \log_{10}(2) = \frac{p}{q}\] where p,q are integers  \[ 10^{\frac{p}{q}} = 2\]  \[ 10^{p-q}} 10^{p-q}  = 2 \] $ \nexists$ two integers for p,q.  \\Also  \[ (10^{\frac{p}{q}})^q = 2^q\] 
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\[ m^{p-q} = n\]   The difference between two integers is an integer. Then m raise to a certain power will have to equal n.   \item \textbf{For a positive integer n, when can $n^{1/n}$ be a rational number (other than n=1)?}  \end{itemize}