deletions | additions       diff --git a/begin_itemize_item_textbf_Show__.tex b/begin_itemize_item_textbf_Show__.tex  index 28aa0cf..c15f978 100644  --- a/begin_itemize_item_textbf_Show__.tex  +++ b/begin_itemize_item_textbf_Show__.tex 
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Proof by contradiction.  \[2^{\log_2 (3) = 3} \]  \[ 2^\frac{p}{q} = 3 \]  $2^{p} \[$2^{p}  - 2^{q} = 3$ 3\]  $\nexists$ two integers for p,q. Also \[ (2^\frac{p}{q})^q = (3)^q \]  \[ 2^p = 3^q \]  $2^p$ will always be even and $3^q$ will always be odd.