deletions | additions       diff --git a/begin_itemize_item_textbf_sqrt__.tex b/begin_itemize_item_textbf_sqrt__.tex  index 3ad48ad..df0e33b 100644  --- a/begin_itemize_item_textbf_sqrt__.tex  +++ b/begin_itemize_item_textbf_sqrt__.tex 
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\begin{itemize}  \item \textbf{\sqrt{2} \textbf{$\sqrt{2}$  is not rational:} \item \textbf{Explain why the following two statements are equivalent:}  \sqrt{2} \\ \textbf{$\sqrt{2}$  is a rational number;  There number;}  \textbf{There  is an integer n>0 $n>0$  such that n\sqrt{2} $n\sqrt{2}$  is an integer}    \\The two statements are equivalent because both are false.  \\ $\sqrt{2}$ is not a rational number.  \\ The product of two integers will always be an integer. The product of a  integer and an irrational is not an integer. Since $\sqrt{2}$ is irrational, $n\sqrt{2}$ is not an integer.  \item \textbf{Show that $\log _2(3)$ is not a rational number.}