Dat Do edited beginproblem__Consid.tex  almost 10 years ago

Commit id: e22d52afddd44ddced0e7a44f5da121b8375f41e

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Now, we will solve for $\beta$  \\  $v^{"}(n) = \beta _1 n + \beta _2$  \\  $\beta _1 n + \beta _2 = (\beta _1(n-1)+\beta _2) + 3(\beta _1(n-2)+\beta _2) + (\beta _1(n-3) + \beta _2) + 2n$