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Dat Do edited beginproblem__Consid.tex
almost 10 years ago
Commit id: 0def6c69580b83ad798d46346b561e2e90c890c5
deletions | additions
diff --git a/beginproblem__Consid.tex b/beginproblem__Consid.tex
index 1c5220a..ab21031 100644
--- a/beginproblem__Consid.tex
+++ b/beginproblem__Consid.tex
...
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Now, we will solve for $\beta$
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$v^{"}(n) $v^{"}_n = \beta _1 n + \beta _2$
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$\beta _1 n + \beta _2 = (\beta _1(n-1)+\beta _2) + 3(\beta _1(n-2)+\beta _2) + (\beta _1(n-3) + \beta _2) + 2n$
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...
$5\beta _1 = -2$
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$\beta _1 =
-2/5$
$\beta _2 = -4/5$ -\frac{2}{5}$
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$v^{"}(n) $\beta _2 =
-\frac{4}{5}$
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$v^{"}_n = -\frac{2}{5}n - \frac{4}{5}$
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General solution: $v_n = \alpha _1 (-1)^n + \alpha _2 (1+\sqrt{2})^n + \alpha _3 (1-\sqrt{2})^n -\frac{2}{5}n - \frac{4}{5}$