deletions | additions       diff --git a/beginproblem_Let_x_b.tex b/beginproblem_Let_x_b.tex  index 81303e0..4894a13 100644  --- a/beginproblem_Let_x_b.tex  +++ b/beginproblem_Let_x_b.tex 
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\\  $x=1$ and $x=2$ would be prime under the equation $x^2 = 1$ (mod $3$)  \\  However, with the equation $x^2+2$, both $x=1$ and $x=2$ result in 0-  $x^2+2=0$(mod $3$) \\  This means that $3$ evenly divides into $x^2+2$ for $x=1$ and $x=2$, meaning that $y$ is not prime for both of these terms.  \\