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Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: d3e227d5556f2985aa9108a603e37d9cc64e77a4
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We see that each term $W(k+1) = 2W(k) + (k+1)$. so,
\\$W(k+1) = 2(2^{k+1}-k-2) + (k+1)$
\\$W(k+1) = 2^{k+2}-2k-4+k+1$
\\$W(k+1) = 2^{k+2}-k-3$
\qed