Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

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\\*  Base Case: For $W(1)$, $2^{1+1}-1-2 = 1$ which is correct since $W(1) = 1$.  \\  Assume $W(k) = 2^{k+1}-k-2$ 2^{k+1}-k-2$, we must show that $W(k+1) = 2^{k+2}-k-3$  \begin{problem}