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Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: c89c38986926eea26583a0736957e2f25d79f7ae
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We see that each term $W(k+1) = 2W(k) + (k+1)$
\\
So, $W(k+1) = 2(2^{k+1}-k-2) + (k+1)$
\\Multiplying 2, we get: $W(k+1) \\$W(k+1) = 2^{k+2}-2k-4+k+1$
\\After adding like terms, we get: $W(k+1) \\$W(k+1) = 2^{k+2}-k-3$