deletions | additions       diff --git a/beginproblem_a_You_a.tex b/beginproblem_a_You_a.tex  index d16ae3d..b47e6a2 100644  --- a/beginproblem_a_You_a.tex  +++ b/beginproblem_a_You_a.tex 
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We see that each term $W(k+1) = 2W(k) + (k+1)$ so,  \\$W(k+1) = 2(2^{k+1}-k-2) + (k+1)$  \\$W(k+1) = 2^{k+2}-2k-4+k+1$  \\$W(k+1) = 2^{k+2}-k-3$\textit{ 2^{k+2}-k-3$  \\Therefore, $W(n) = 2^{n+1}-n-2$  \textit{  Q.E.D.} \end{proof}