Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

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\item $W(4) = 26$  \item $W(5) = 57$  \end{itemize}  We see that each term $W(k+1) = 2W(k) + (k+1)$. (k+1)$  so, \\$W(k+1) = 2(2^{k+1}-k-2) + (k+1)$  \\$W(k+1) = 2^{k+2}-2k-4+k+1$  \\$W(k+1) = 2^{k+2}-k-3$ Q.E.D.  \end{proof}