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Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: b6720f289301424e2b3268647767a3d345f9aecf
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diff --git a/beginproblem_a_You_a.tex b/beginproblem_a_You_a.tex
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\textbf{Solution 2: }
\textbf{Proof:}
\\*
Base Case: For $n=3$,
$2^3+3^3+4^3 \\$2^3+3^3+4^3 \leq
5^3 = 99 5^3$ \\$99 \leq 125$.
The \\The inequality holds true for $n=3$
\\
Assume: $2^k+3^k+4^k\leq5^k$. We must show that $k+1$, $2^{k+1}+3^{k+1}+4^{k+1}\leq5^{k+1}$