Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

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\smallskip  \noindent  (c) For n $n  = 1 1$  through n $n  = 6, 6$,  $W(1) = 1, W(2) = 4, W(3) = 11, W(4) = 26, W(5) = 57, W(6) 57$  We know that the closed form expression should involve a value slightly larger than $2^n$, so we try $2^{n+1}$ and get \begin{itemize}  \item $n  = 120$ 1$ as $4$  \item $n = 2$ as $8$  \item $n = 3$ as $16$  \item $n = 4$ as $32$  \item $n = 5$ as $64$  \end{itemize}