Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

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\item $W(4) = 26$  \item $W(5) = 57$  \end{itemize}  We see that each term $W(k+1) = 2(W(k)) 2W(k)  + (k+1)$ \\  So, $W(k+1) = 2(2^{k+1}-k-2) + (k+1)$  \\Multiplying 2, we get: $W(k+1) = 2^{k+2}-2k-4+k+1$  \\After adding like terms, we get: $W(k+1) = 2^{k+2}-k-3$