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Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: 984a3b311551ebc0e6f18d82e79ffbecb60d8c1d
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diff --git a/beginproblem_a_You_a.tex b/beginproblem_a_You_a.tex
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\item $2^{5+1} = 64$
\end{itemize}
The difference between $2^{n+1}$ and $W(n)$ appears to be $-n-2$ for each term, so the closed form expression for $W(n)$ must be $\sum\limits_{i=1}^n i*2^{n-i} = 2^{n+1}-n-2$. We can prove that this expression is correct using
induction: induction.
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\textbf{Proof:}
\\*
Base Case: For
$n=1$ $n=1$, $2^{1+1}-1-2 = 1$ which is correct.
\begin{problem}