Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

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\smallskip  \noindent  (c) For $n = 1$ through $n = 6$, \begin{enumerate}  \item  $W(1) = 1, W(2) 1$  \item $W(2)  = 4, W(3) 4$   \item $W(3)  = 11, W(4) 11$   \item $W(4)  = 26, W(5) 26$  \item $W(5)  = 57$ \end{enumerate}  We know that the closed form expression should involve a value slightly larger than $2^n$, so we try $2^{n+1}$ and get \begin{itemize}  \item $n = 1$ as $4$  \item $n = 2$ as $8$