Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

Commit id: 762b909dd1ef033245db54b976e9389fcff9e5b0

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\item $W(4) = 26$  \item $W(5) = 57$  \end{itemize}  We know that the closed form expression should involve a value slightly larger than $2^n$, so we try try:  $2^{n+1}$ and get \begin{itemize} \item $n = 1$ as $4$  \item $n = 2$ as $8$  \item $n = 3$ as $16$ 

\item $n = 5$ as $64$  \end{itemize}  The summation can difference between $2^{n+1}$ and $W(n)$ appears to  be represented in -n-2 for each term, so the  closed form as so: $W(n) = \sum\limits_{i=1}^n expression for $W(n)$ must be $\sum\limits_{i=1}^n  i*2^{n-i} = 2^{n+1}-n-2$ \begin{problem}