deletions | additions       diff --git a/beginproblem_a_You_a.tex b/beginproblem_a_You_a.tex  index e2c67cd..771578c 100644  --- a/beginproblem_a_You_a.tex  +++ b/beginproblem_a_You_a.tex 
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Base Case: For $W(1)$, $2^{1+1}-1-2 = 1$ which is correct since $W(1) = 1$.  \\  Assume $W(k) = 2^{k+1}-k-2$, we must show that $W(k+1) = 2^{k+2}-k-3$  \\  Based off of the sequence $W(n)$  \begin{itemize}  \item $W(1) = 1$  \item $W(2) = 4$   \item $W(3) = 11$   \item $W(4) = 26$  \item $W(5) = 57$  \end{itemize}  We see that each term $W(k+1) = 2(W(k)) + (k+1)$