Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

Commit id: 43bd5ea1ef8501593359f9efe343821617b6dfc6

deletions | additions      

       

We see that each term $W(k+1) = 2W(k) + (k+1)$ so,  \\$W(k+1) = 2(2^{k+1}-k-2) + (k+1)$  \\$W(k+1) = 2^{k+2}-2k-4+k+1$  \\$W(k+1) = 2^{k+2}-k-3$ Q.E.D. 2^{k+2}-k-3$\textit{ Q.E.D.}  \end{proof}