Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

Commit id: 2880f9f397ad971bad164d5a2af20d7d75a88580

deletions | additions      

       

\smallskip  \noindent  (b) Since we are still receiving one extra coupon for each consecutive day, $\sum\limits_{i=1}^k i$ can still represent the number of coupons received. However, the value of the coupons is: $1 + 2 + 4 + 8 + ... \ldots  + 2(n-1)$ 2{n-1}$  which can be represented as $\sum\limits_{i=1}^n 2^(n-i)$. 2^{n-i}$.  \smallskip  We must multiply the quantity and the value together to get the total value resulting in: $\sum\limits_{i=1}^n i*2^(n-i)$ i*2^{n-i}$