Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

Commit id: 26ccb29c110851a4c60f0a369c9be904b1602270

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\smallskip  \noindent  (b) Since we are still receiving one extra coupon for each consecutive day, $\sum\limits_{i=1}^k i$ can still represent the number of coupons received. However, the value of the coupons  is: $1 + 2 + 4 + 8 + ... + 2(n-1)$ which can be represented as $\sum\limits_{i=1}^k 2^n-i$ $\sum\limits_{i=1}^n 2^(n-i)$.   \smallskip  We must multiply the quantity and the value together to get the total value resulting in: $\sum\limits_{i=1}^n i * 2^(n-i)$