this is for holding javascript data
Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: 2218fc5b09e61e00cd2eb21df972df0a19739383
deletions | additions
diff --git a/beginproblem_a_You_a.tex b/beginproblem_a_You_a.tex
index e2ddf33..f9b8337 100644
--- a/beginproblem_a_You_a.tex
+++ b/beginproblem_a_You_a.tex
...
\item $n = 5$ as $64$
\end{itemize}
The difference between $2^{n+1}$ and $W(n)$ appears to be
-n-2 $-n-2$ for each term, so the closed form expression for $W(n)$ must be $\sum\limits_{i=1}^n i*2^{n-i} = 2^{n+1}-n-2$
\begin{problem}