Dat Do edited beginproblem_a_You_a.tex  about 10 years ago

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\smallskip  \noindent  (c) For $n = 1$ through $n = 6$, \begin{itemize} \item $W(1) = 1$  \item $W(2) = 4$   \item $W(3) = 11$   \item $W(4) = 26$  \item $W(5) = 57$  \end{itemize}  We know that the closed form expression should involve a value slightly larger than $2^n$, so we try the same $n$ values for: for  $2^{n+1}$ and get get:  \begin{itemize} \item $2^{1+1} = 4$  \item $2^{2+1} = 8$  \item $2^{3+1} = 16$