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\item $2^{5+1} = 64$  \end{itemize}  The difference between $2^{n+1}$ and $W(n)$ appears to be $-n-2$ for each term, so the closed form expression for $W(n)$ must be $\sum\limits_{i=1}^n i*2^{n-i} = 2^{n+1}-n-2$  \\* 2^{n+1}-n-2$.  We can prove that this expression is correct using induction  \\* induction:  \\  \textbf{Proof:}  \\*  Base Case: For $n=1$