this is for holding javascript data
Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: 16f6b218e8cfeccb575363408eae092c6c3d0f13
deletions | additions
diff --git a/beginproblem_a_You_a.tex b/beginproblem_a_You_a.tex
index 28cc883..5c1ee49 100644
--- a/beginproblem_a_You_a.tex
+++ b/beginproblem_a_You_a.tex
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\item $2^{5+1} = 64$
\end{itemize}
The difference between $2^{n+1}$ and $W(n)$ appears to be $-n-2$ for each term, so the closed form expression for $W(n)$ must be $\sum\limits_{i=1}^n i*2^{n-i} =
2^{n+1}-n-2$
\\* 2^{n+1}-n-2$. We can prove that this expression is correct using
induction
\\* induction:
\\
\textbf{Proof:}
\\*
Base Case: For $n=1$